sql - MySQL: Union, Count, and Group By -

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( select root_tags.tag_id, root_tags.tag_name, count( root_tagged.pg_id ) root_tags  left join root_tagged on ( root_tagged.tag_id = root_tags.tag_id ) left join root_pages on ( root_pages.pg_id =  root_tagged.pg_id ) left join root_granted on ( root_granted.pg_id =  root_tagged.pg_id )  root_pages.parent_id = '5' , root_granted.mem_id = '3'  group root_tags.tag_id order 3 desc )  union ( select root_tags.tag_id, root_tags.tag_name, count( root_tagged.pg_id ) root_tags  left join root_tagged on ( root_tagged.tag_id = root_tags.tag_id ) left join root_pages on ( root_pages.pg_id =  root_tagged.pg_id )  root_pages.parent_id = '5' , not exists (     select *     root_granted     root_granted.pg_id =  root_pages.pg_id )  group root_tags.tag_id order 3 desc )

the query above returns result below,

tag_id  tag_name                count(root_tags.tag_id) 16      expert-category-c       2 14      expert-category-a       1 15      expert-category-b       1 16      expert-category-c       1

as can see tag_id 16 repeated, how can rewrite query tag_id 16 has count number of 3, mean want query supposed return result this,

tag_id  tag_name                count(root_tags.tag_id) 16      expert-category-c       3 14      expert-category-a       1 15      expert-category-b       1

i tried query returns error...

( select root_tags.tag_id, root_tags.tag_name, count( root_tagged.pg_id ) root_tags  left join root_tagged on ( root_tagged.tag_id = root_tags.tag_id ) left join root_pages on ( root_pages.pg_id =  root_tagged.pg_id ) left join root_granted on ( root_granted.pg_id =  root_tagged.pg_id )  root_pages.parent_id = '5' , root_granted.mem_id = '3'  )  union ( select root_tags.tag_id, root_tags.tag_name, count( root_tagged.pg_id ) root_tags  left join root_tagged on ( root_tagged.tag_id = root_tags.tag_id ) left join root_pages on ( root_pages.pg_id =  root_tagged.pg_id )  root_pages.parent_id = '5' , not exists (     select *     root_granted     root_granted.pg_id =  root_pages.pg_id ) )  group root_tags.tag_id order 3 desc

could please let me know how make work?

thanks.

the better query given further below, upon analyzing actual query.

you can merge 2 queries using union instead of union (to retain duplicates), run group across entire set.

select tag_id, tag_name, sum(counttags) counttags ( select root_tags.tag_id, root_tags.tag_name, count( root_tagged.pg_id ) counttags root_tags  left join root_tagged on ( root_tagged.tag_id = root_tags.tag_id ) left join root_pages on ( root_pages.pg_id =  root_tagged.pg_id ) left join root_granted on ( root_granted.pg_id =  root_tagged.pg_id )  root_pages.parent_id = '5' , root_granted.mem_id = '3'  group root_tags.tag_id  union  select root_tags.tag_id, root_tags.tag_name, count( root_tagged.pg_id ) counttags root_tags  left join root_tagged on ( root_tagged.tag_id = root_tags.tag_id ) left join root_pages on ( root_pages.pg_id =  root_tagged.pg_id )  root_pages.parent_id = '5' , not exists (     select *     root_granted     root_granted.pg_id =  root_pages.pg_id )  group root_tags.tag_id ) sq group tag_id, tag_name order counttags desc

since clauses filter against root_granted , root_pages, inner joins. can use exists test emulate first part of union, assuming can never have more 1 root_granted record per root_pages record.

select root_tags.tag_id, root_tags.tag_name, count( root_tagged.pg_id ) counttags root_tags inner join root_tagged on ( root_tagged.tag_id = root_tags.tag_id ) inner join root_pages on ( root_pages.pg_id =  root_tagged.pg_id ) root_pages.parent_id = '5' , (not exists (     select *     root_granted     root_granted.pg_id =  root_pages.pg_id ) or exists (     select *     root_granted     root_granted.pg_id =  root_pages.pg_id , root_granted.mem_id = '3')) group root_tags.tag_id, root_tags.tag_name order counttags desc

since not exists , exists mutually exclusive, can combine them using or single query.


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