php - How ffmpeg is command executed in this code -

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want know how ffmpeg command executed taking screenshot in code. not able figure out when screenshot created, function or line done.

  $ffmpeg = '/usr/bin/ffmpeg';         $video  = $sourceurl;// input video file         $thumbid = uniqid();         $thumbid .= ".jpg";         // you'll save image         $image = "uploads/$thumbid";         // default time image         $second = 1;         // duration , random place within         $cmd = "$ffmpeg -i $video 2>&1";         if (preg_match('/duration: ((\d+):(\d+):(\d+))/s', `$cmd`, $time)) {             $total = ($time[2] * 3600) + ($time[3] * 60) + $time[4];             $second = rand(1, ($total - 1));         }          // screenshot         $cmd = "$ffmpeg -i $video -deinterlace -an -ss $second -t 00:00:01 -r 1 -y -s 120x90 -vcodec mjpeg -f mjpeg $image 2>&1";         $return = `$cmd`;         $thumblink = "";

this line executes command stored in variable $cmd:

    $return = `$cmd`;

in php, backtick execution operator, , use identical calling shell_exec.


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