c++ - Why is it not possible to define a fully-qualified function within a foreign namespace? May I know what the standard says? -

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is wrong? why? may know standard says?

 namespace n{   namespace n1{      namespace n2{         struct a{          struct b{           void fun();        };//b      }; //a    } //n2  }//n1  namespace n3{      void n1::n2::a::b::fun(){} //error  }//n3 }//n  int main()  {   return 0;  }

may know why failing?

this invalid due §9.3/2:

a member function definition appears outside of class definition shall appear in namespace scope enclosing class definition.

the scope of namespace n3 not enclose definition of class b


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